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Proof step 1 from proof replay-lpt-size (conclusion)

n ≤ # lpt ⊦ # replay-lpt(lpt, nx, n) = # lpt

User applied rule structural induction

And obtained the following new goals

Proof step 2:
n0 +1 ≤ # lpt, ∀ lpt, nx. n0 ≤ # lpt → # replay-lpt(lpt, nx, n0) = # lpt ⊦ # replay-lpt(lpt, nx, n0 +1) = # lpt

Rule argument

indvar: n

Additional information

Used simplifier rules: replay-lpt-base: ⊦ replay-lpt(lpt, nx, 0) = lpt;%nat freely generated by 0, +1;;