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Proof step 11 from proof replay-lpt-size (previous step)

lpt[n0] = mklp(m, m0, lpf, m1), n0 < # lpt, ∀ lpt, nx. n0 ≤ # lpt → # replay-lpt(lpt, nx, n0) = # lpt, lpf ≠ LP_INDEX_NODES ∨ m = 0 ⊦ # (m = 0 ⊃ replay-lpt(lpt, nx, n0)[n0, mklp(0, 0, LP_FREE, m1)];replay-lpt(lpt, nx, n0)) = # lpt, lpf = LP_FREE, n0 ∈ nx

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 12:
lpt[n0] = mklp(m, m0, lpf, m1), m = 0, n0 < # lpt, ∀ lpt, nx. n0 ≤ # lpt → # replay-lpt(lpt, nx, n0) = # lpt, lpf ≠ LP_INDEX_NODES ∨ m = 0 ⊦ # replay-lpt(lpt, nx, n0)[n0, mklp(0, 0, LP_FREE, m1)] = # lpt, lpf = LP_FREE, n0 ∈ nx
Proof step 14:
lpt[n0] = mklp(m, m0, lpf, m1), n0 < # lpt, ∀ lpt, nx. n0 ≤ # lpt → # replay-lpt(lpt, nx, n0) = # lpt, lpf ≠ LP_INDEX_NODES ∨ m = 0 ⊦ # replay-lpt(lpt, nx, n0) = # lpt, lpf = LP_FREE, m = 0, n0 ∈ nx

Rule argument

pos: right 1

Proof step 11 from proof replay-lpt-size (previous step)

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

Additional information