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Proof step 1 from proof fidb-diff-one (conclusion)

⊦ fid0 ∈ fidb ∧ fid0 ≠ fid1 → fid0 ∈ fidb \ {fid1}

System applied rule normalize

And obtained the following new goals

Proof step 2:
fid0 ∈ fidb ⊦ fid0 = fid1, fid0 ∈ fidb \ {fid1}

Rule argument

Additional information