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Proof step 30 from proof fids-put1 (previous step)

tree[p0, tree1].fids = (tree.fids ∪ tree1.fids) \ tree[p0].fids, tree[parent(p0)].dir?, p0 ∈ tree, tree[p0].fids ⊆ tree.fids ⊦ p0 = ε, sdt0.fids ∪ tree[p0, tree1].fids = ((sdt0.fids ∪ tree.fids) ∪ tree1.fids) \ tree[p0].fids, str ∈ sdt0

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

Additional information