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Proof step 33 from proof fids-put1 (previous step)

tree[parent(p0)].dir?, p0 ∈ tree, tree[p0].fids ⊆ tree.fids ⊦ p0 = ε, sdt0.fids ∪ ((tree.fids ∪ tree1.fids) \ tree[p0].fids) = ((sdt0.fids ∪ tree.fids) ∪ tree1.fids) \ tree[p0].fids, str ∈ sdt0, tree[p0].fids ⊆ tree.fids ∪ tree1.fids

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 34:
tree[parent(p0)].dir?, p0 ∈ tree, tree[p0].fids ⊆ tree.fids ⊦ p0 = ε, sdt0.fids ∪ ((tree.fids ∪ tree1.fids) \ tree[p0].fids) = ((sdt0.fids ∪ tree.fids) ∪ tree1.fids) \ tree[p0].fids, str ∈ sdt0, tree[p0].fids ⊆ tree.fids ∪ tree1.fids

Proof step 33 from proof fids-put1 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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