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Proof step 18 from proof fids-put2 (previous step)

tree[parent(p0)].dir?, parent(p0) ∈ tree, ∀ tree, tree0. tree[parent(p0)].dir? ∧ parent(p0) ∈ tree → tree[p0, tree0].fids = tree.fids ∪ tree0.fids ∨ p0 ∈ tree ⊦ tree[p0, tree1].fids = tree.fids ∪ tree1.fids, p0 = ε, str ∈ sdt0, p0 ∈ tree

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: tree, tree1

Additional information

Used terms: tree, tree1