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Proof step 6 from proof fids-str (previous step)

sdt[str][p] = fnode(fid), p ∈ sdt[str], str ∈ sdt ⊦ fid ∈ sdt.fids

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: fids-strpath seq: ⊦ fid ∈ sdt.fids ↔ (∃ str, p. str ∈ sdt ∧ p ∈ sdt[str] ∧ sdt[str][p] = fnode(fid)) subst: [sdt, fid] → [sdt, fid] flags: <all paths>

Additional information

Used terms: sdt, fid