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Proof step 7 from proof Del-empty (
previous step
)
⊦ (∅ -- str)[str] = (∅)[str], str ∈ ∅ -- str
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 8
:
⊦ ¬ str ∈ sdt → sdt[str] = (∅)[str]
Rule argument
spec: <toplevel> name: read-notin seq: ⊦ ¬ str ∈ sdt → sdt[str] = (∅)[str] subst: [str, sdt] → [str, ∅ -- str] flags: <all paths>
Additional information
Used terms: str, ∅ -- str