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Proof step 12 from proof Del-rec-other (previous step)

str1 = str ⊦ (sdt[str0, tree] -- str)[str1] = (sdt -- str)[str0, tree][str1], str = str0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
⊦ (sdt[str0, tree] -- str)[str] = (sdt -- str)[str], str = str0

Rule argument

Additional information

Used simplifier rules: ⊦ str ≠ str0 → sdt[str0, tree][str] = sdt[str]; (s)