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Proof step 7 from proof Del-rec-other (previous step)

⊦ str1 ∈ sdt[str0, tree] -- str ↔ str1 ∈ (sdt -- str)[str0, tree], str = str0, str1 ∈ sdt[str0, tree] -- str

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
str1 ∈ (sdt -- str)[str0, tree] ⊦ str = str0, str1 ∈ sdt[str0, tree] -- str

Rule argument

Additional information