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Proof step 16 from proof again-put (previous step)

p0 ∈ sdt[str], str ∈ sdt, ∀ tree. p0 ∈ tree → tree[p0, tree[p0]] = tree ∨ p0 = ε ⊦ dnode(md, sdt[str, sdt[str][p0, sdt[str][p0]]]) = dnode(md, sdt), p0 = ε

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
str ∈ sdt, p0 ∈ sdt[str], ∀ tree. p0 ∈ tree → tree[p0, tree[p0]] = tree ⊦ dnode(md, sdt[str, sdt[str][p0, sdt[str][p0]]]) = dnode(md, sdt), p0 = ε

Proof step 16 from proof again-put (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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