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Proof step 1 from proof at-mod (conclusion)

tree[p] = dnode(md0, sdt0) ⊦ tree.dir? ∧ p ∈ tree ∧ q ∈ tree[p, dnode(md1, sdt1)] → tree[p, dnode(md1, sdt1)][q] = (q ⊑ p ⊃ tree[q][restn(# q, p), dnode(md1, sdt1)];tree[p, dnode(md0, sdt1)][q])

System applied rule normalize

And obtained the following new goals

Proof step 2:
tree[p] = dnode(md0, sdt0), tree.dir?, p ∈ tree, q ∈ tree[p, dnode(md1, sdt1)] ⊦ tree[p, dnode(md1, sdt1)][q] = (q ⊑ p ⊃ tree[q][restn(# q, p), dnode(md1, sdt1)];tree[p, dnode(md0, sdt1)][q])

Proof step 1 from proof at-mod (conclusion)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information