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Proof step 3 from proof dnode-onein (previous step)
| str ' ∈ tree ⊦ ∃ md, sdt. tree = dnode(md, sdt) ∧ str ∈ sdt |
User applied rule constructor cut
And obtained the following new goals
- Proof step 4:
tree = dnode(md0, sdt0), str ' ∈ tree ⊦ ∃ md, sdt. tree = dnode(md, sdt) ∧ str ∈ sdt
- Proof step 7:
⊦ str ' ∈ fnode(fid) ↔ false
Rule argument
var: treeAdditional information
Used simplifier rules:
one-inf: ⊦ str ' ∈ fnode(fid) ↔ false;%directory-tree, entries-tree generated by ∅, dnode, fnode, [ ];;