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Proof step 37 from proof in-put (previous step)

sdt0[str0] = dnode(md, sdt), q0 ∈ dnode(md, sdt[str, tree0]), str0 ∈ sdt0, str ' ⊑ q0, ∀ md1, sdt1, md2, sdt2, q, str2, tree. dnode(md1, sdt1) = dnode(md2, sdt2) → (q ∈ dnode(md2, sdt2[str2, tree]) ↔ (str2 ' ⊑ q ⊃ q.tail ∈ tree;q ∈ dnode(md1, sdt1))) ⊦ q0.tail ∈ tree0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 38:
⊦ str ' + p ∈ dnode(md, sdt) ↔ str ∈ sdt ∧ p ∈ sdt[str]

Rule argument

spec: list-data, inst: path name: elim-list-c seq: p ≠ ε ⊦ str = p.head ∧ p0 = p.tail ↔ p = str + p0 subst: [p, str, p0] → [q0, str1, p]

Additional information

Used simplifier rules: in-dnode: ⊦ str ' + p ∈ dnode(md, sdt) ↔ str ∈ sdt ∧ p ∈ sdt[str];% ⊦ str + p = str ' + p; (s)% ⊦ str ' + p ≠ ε; (s)%a: ⊦ (p + p0) + p1 = p + p0 + p1; from specification list[path]% ⊦ str ' ⊑ str0 ' + p ↔ str = str0; (s)% ⊦ str = str0 → sdt[str0, tree][str] = tree; (s)% ⊦ p ⊑ ε ↔ p = ε; (s)% ⊦ str ' ≠ ε; (s)%p ≠ ε ⊦ str = p.head ∧ p0 = p.tail ↔ p = str + p0; (elim) Used terms: q0, str1, p