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Proof step 2 from proof notin-del (previous step)

p ∈ tree -- p, p ∈ tree ⊦ p = ε

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
p ≠ ε ⊦ p ∈ tree → (q ∈ tree -- p ↔ ¬ p ⊑ q ∧ q ∈ tree)

Rule argument

Additional information

Used simplifier rules: in-del: p ≠ ε ⊦ p ∈ tree → (q ∈ tree -- p ↔ ¬ p ⊑ q ∧ q ∈ tree);% ⊦ p ⊑ p; (s)