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Proof step 5 from proof put-fnode (
previous step
)
tree[p, tree0] = fnode(fid), tree = dnode(md, sdt), p ∈ tree ⊦ p = ε ∧ tree0 = fnode(fid)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
dnode(md, sdt)[p, tree0] = fnode(fid), p ∈ dnode(md, sdt) ⊦ p = ε ∧ tree0 = fnode(fid)
Rule argument
Additional information