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Proof step 1 from proof restn-len (conclusion)

# p ≤ # q ⊦ restn(# p, q) = ε ↔ # p = # q

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ # p = n → restn(n, p) = ε; (s)% ⊦ n ≤ # p → (restn(n, p) = ε ↔ n = # p); (s)