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Proof step 12 from proof split-at (
previous step
)
str ∈ sdt, p0 ∈ sdt[str], ∀ tree, q. p0 ∈ tree → tree[p0 + q] = tree[p0][q] ⊦ sdt[str][p0 + q] = sdt[str][p0][q]
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 3 terms: sdt[str], q
Additional information
Used terms: sdt[str], q