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Proof step 8 from proof split-restn (previous step)

p0 ⊑ p1, ∀ q0, q1. p0 ⊑ q0 → restn(# p0, q0 + q1) = restn(# p0, q0) + q1 ⊦ restn(# p0, p1 + q1) = restn(# p0, p1) + q1

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: p1, q1

Additional information

Used terms: p1, q1