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Proof step 8 from proof ex-minimal-new-fd (previous step)

⊦ ∃ fd. ¬ fd ∈ ofh ∧ (∀ m. ¬ m ∈ ofh → fd ≤ m), ∃ n. ¬ n ∈ ofh

User applied rule exists right

And obtained the following new goals

Proof step 9:
max(ofh) + 1 ∈ ofh ⊦ ∃ fd. ¬ fd ∈ ofh ∧ (∀ m. ¬ m ∈ ofh → fd ≤ m)

Rule argument

pos: right 2 terms: max(ofh) + 1 abort: F discard: T computed: F

Additional information

Used terms: max(ofh) + 1