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Proof step 4 from proof fid-in-fs (previous step)

ofh[fd] = mkfh(fid, mode, m), fd ∈ ofh, ∀ fid. fid ∈ fs ↔ fid ∈ root.fids ∨ fid ∈ ofh.fids ⊦ fid ∈ fs

User applied rule all left

And obtained the following new goals

Proof step 5:
fid ∈ fs ↔ fid ∈ root.fids ∨ fid ∈ ofh.fids, ofh[fd] = mkfh(fid, mode, m), fd ∈ ofh, ∀ fid. fid ∈ fs ↔ fid ∈ root.fids ∨ fid ∈ ofh.fids ⊦ fid ∈ fs

Rule argument

pos: left 3 terms: fid abort: F discard: F computed: T

Additional information

Used terms: fid