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Proof step 7 from proof fids-exists (previous step)

dnode(md, sdt) = tree0, ∀ str. str ∈ sdt → (∃ fids. ∀ fid. fid ∈ fids ↔ fid ∈ sdt[str].fids) ⊦ ∃ fids. ∀ fid0. fid0 ∈ fids ↔ fid0 ∈ sdt.fids

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information