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Proof step 8 from proof inv-recover (previous step)

err = err0, fs = fs0, ofh = ofh0, tree.dir?, fids-cons(tree, fs1, ofh1), posix-crash(tree, fs1, ofh1, root, fs0, ofh0), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err ≠ ESUCCESS then root := ?, fs := ?, ofh := ?, psynced := ? else psynced := true⟫ (err = ESUCCESS → psynced ∧ root.dir? ∧ fids-cons(root, fs, ofh))

Heuristic conditional right split applied rule if right

And obtained the following new goals

Proof step 9:
err = err0, fs = fs0, ofh = ofh0, tree.dir?, fids-cons(tree, fs1, ofh1), posix-crash(tree, fs1, ofh1, root, fs0, ofh0), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪root := ?, fs := ?, ofh := ?, psynced := ?⟫ (err = ESUCCESS → psynced ∧ root.dir? ∧ fids-cons(root, fs, ofh)), err = ESUCCESS
Proof step 10:
err = ESUCCESS, err = err0, fs = fs0, ofh = ofh0, tree.dir?, fids-cons(tree, fs1, ofh1), posix-crash(tree, fs1, ofh1, root, fs0, ofh0), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪psynced := true⟫ (err = ESUCCESS → psynced ∧ root.dir? ∧ fids-cons(root, fs, ofh))

Rule argument

pos: right 1

Proof step 8 from proof inv-recover (previous step)

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

Additional information