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Proof step 15 from proof inv-renam (previous step)

psynced0 ↔ path' ∈ root, err = ESUCCESS, err0 = err1, tree = root[path'], tree0 = root[path], root.dir?, fids-cons(root, fs, ofh), pre-renam(path, path', err, user, root, fs, ofh) ⊦ ⟪if psynced0 ∧ ¬ tree.dir? ∧ ¬ tree.fid ∈ ofh.fids ∧ ¬ tree.fid ∈ (root -- path)[path', tree0].fids then fs := fs -- tree.fid; psynced := ?⟫ true

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

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