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Proof step 9 from proof inv-write (previous step)

err = ESUCCESS, err0 = err1, fh = ofh[fd], n0 = n, root.dir?, fids-cons(root, fs, ofh), pre-write(fd, buf, n0, err, user, root, fs, ofh), fd ∈ ofh, n ≤ # buf ⊦ ⟪let f = fs[fh.fid] in choose n with n ≤ n0 in {n0 := n; f.content := splice(buf, 0, f.content, fh.pos, n0); fs[fh.fid] := f; ofh[fd].pos := fh.pos + n0}; psynced := ?⟫ fids-cons(root, fs, ofh)

Heuristic symbolic execution applied rule let right

And obtained the following new goals

Proof step 10:
err = ESUCCESS, err0 = err1, f = fs[fh.fid], fh = ofh[fd], n0 = n, root.dir?, fids-cons(root, fs, ofh), pre-write(fd, buf, n0, err, user, root, fs, ofh), fh.fid ∈ fs, fd ∈ ofh, n ≤ # buf ⊦ ⟪choose n with n ≤ n0 in {n0 := n; f.content := splice(buf, 0, f.content, fh.pos, n0); fs[fh.fid] := f; ofh[fd].pos := fh.pos + n0}; psynced := ?⟫ fids-cons(root, fs, ofh)
Proof step 23:
err = ESUCCESS, err0 = err1, fh = ofh[fd], n0 = n, root.dir?, fids-cons(root, fs, ofh), pre-write(fd, buf, n0, err, user, root, fs, ofh), fd ∈ ofh, n ≤ # buf ⊦ fh.fid ∈ fs

Proof step 9 from proof inv-write (previous step)

Heuristic symbolic execution applied rule let right

And obtained the following new goals

Rule argument

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