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Proof step 59 from proof rename-fids (previous step)

root0[path].dir? ↔ root0[path'].dir?, fid ∈ fs ↔ fid ∈ root0.fids ∨ fid ∈ ofh.fids, dnode(md, sdt) = root0[path], root0[parent(path')].dir?, (root0 -- path)[parent(path')].dir?, fids-cons(root0, fs, ofh), py(user, parent(path'), root0, fs), py(user, parent(path), root0, fs), parent(path') ∈ root0, path ∈ root0, path' ∈ root0, root0[path'].dir? → root0[path'].entries = ∅, root0[path'].dir? → pw(user, path, root0, fs) ⊦ fid ∈ fs ↔ fid ∈ ((root0.fids \ root0[path].fids) \ (path' ⊑ path ⊃ root0[path'] -- restn(# path', path);root0[path']).fids) ∪ root0[path].fids ∨ fid ∈ ofh.fids, path' = ε, path ⊑ path', ¬ root0[path'].dir? ∧ ¬ root0[path'].fid ∈ ofh.fids ∧ ¬ root0[path'].fid ∈ ((root0.fids \ root0[path].fids) \ (path' ⊑ path ⊃ root0[path'] -- restn(# path', path);root0[path']).fids) ∪ root0[path].fids

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 60:
root0[path'].entries = ∅, fid ∈ fs ↔ fid ∈ root0.fids ∨ fid ∈ ofh.fids, dnode(md, sdt) = root0[path], root0[parent(path')].dir?, (root0 -- path)[parent(path')].dir?, root0[path'].dir?, fids-cons(root0, fs, ofh), pw(user, path, root0, fs), py(user, parent(path'), root0, fs), py(user, parent(path), root0, fs), parent(path') ∈ root0, path ∈ root0, path' ∈ root0 ⊦ fid ∈ fs ↔ fid ∈ ((root0.fids \ sdt.fids) \ (path' ⊑ path ⊃ root0[path'] -- restn(# path', path);root0[path']).fids) ∪ sdt.fids ∨ fid ∈ ofh.fids, path' = ε, path ⊑ path'

Rule argument

Additional information

Used simplifier rules: ⊦ dnode(md, sdt).fids = sdt.fids; (s)% ⊦ dnode(md, sdt).dir?; (s)