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Proof step 4 from proof crash-exists (previous step)

∀ fid. fid ∈ fs ↔ fid ∈ tree0.fids ∧ fid ∈ fs0, ∀ fid. fid ∈ fs → fs[fid] = fs0[fid] ⊦ ∃ tree1, fs1, ofh1. posix-crash(tree0, fs0, ofh0, tree1, fs1, ofh1)

User applied rule exists right

And obtained the following new goals

Rule argument

pos: right 1 terms: tree0, fs, ∅ abort: F discard: T computed: F

Additional information

Used terms: tree0, fs, ∅