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Proof step 2 from proof ofh-fids-mod (previous step)

ofh[fd] = mkfh(fid, mode0, n0), fd ∈ ofh ⊦ ofh[fd, mkfh(fid, mode1, n1)].fids = ofh.fids

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information