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Proof step 3 from proof links1 (previous step)

⊦ ∀ p. p ∈ links(fid, fnode(fid0)) ↔ p ∈ (fid = fid0 ⊃ {ε} ;∅)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ p ∈ links(fid, fnode(fid0)) ↔ p ∈ (fid = fid0 ⊃ ∅ ++ ε;∅)

Rule argument

Additional information

Used simplifier rules: ⊦ {p} = ∅ ++ p; (s)