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Proof step 8 from proof plinksd+ (previous step)

⊦ p ∈ links(fid, dnode(md, sdt[str, tree])) ↔ p ∈ links(fid, dnode(md, sdt)) ∨ p ∈ str + links(fid, tree), str ∈ sdt

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ p ∈ str + ps ↔ p ≠ ε ∧ p.head = str ∧ p.tail ∈ ps
Proof step 10:
⊦ p ∈ links(fid, dnode(md, sdt[str, tree])) ↔ p ∈ links(fid, dnode(md, sdt)) ∨ p ≠ ε ∧ p.head = str ∧ p.tail ∈ links(fid, tree), str ∈ sdt

Rule argument

Additional information

Used simplifier rules: in-consp: ⊦ p ∈ str + ps ↔ p ≠ ε ∧ p.head = str ∧ p.tail ∈ ps;