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Proof step 5 from proof inv-isbad (previous step)

n < # apebs, ubi-io-inv(apebs) ⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err = ESUCCESS then isbad := apebs[n].bad else isbad := ?⟫ true

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Proof step 6:
n < # apebs, ubi-io-inv(apebs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err = ESUCCESS then isbad := apebs[n].bad else isbad := ?⟫ true
Proof step 10:
n < # apebs, ubi-io-inv(apebs) ⊦ ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Proof step 5 from proof inv-isbad (previous step)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information