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Proof step 7 from proof inv-isbad (previous step)

n < # apebs, ubi-io-inv(apebs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err0 = ESUCCESS then isbad := apebs[n].bad else isbad := ?⟫ true

Heuristic conditional right split applied rule if right

And obtained the following new goals

Proof step 8:
err0 = ESUCCESS, n < # apebs, ubi-io-inv(apebs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪isbad := apebs[n].bad⟫ true
Proof step 9:
n < # apebs, ubi-io-inv(apebs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪isbad := ?⟫ true, err0 = ESUCCESS

Rule argument

pos: right 1

Additional information