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Proof step 15 from proof inv-sync-erase (previous step)

apebs[n] = mkpeb(aehdr, avhdr, buf, m, false), n < # apebs, ubi-io-inv(apebs), ubi-io-peb-inv(apeb), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪apebs[n] := apeb⟫ ubi-io-inv(apebs), err0 = ESUCCESS, apeb.bad, apeb.vidhdr.valid?

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ ubi-io-inv(apebs) → ( ubi-io-inv(apebs[n, apeb]) ↔ n < # apebs ∧ ubi-io-peb-inv(apebs[n]) → ubi-io-peb-inv(apeb)); (ss)