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Proof step 8 from proof abs-peb-empty (previous step)

aehdr = empty, avhdr = empty, buf = mkempbuf(LEB_SIZE) ⊦ (aehdr ≠ empty → avhdr ≠ empty ∧ 0 = m0 + 2 * EB_PAGE_SIZE) ∧ ¬ aehdr.valid? ∧ aehdr ≠ garbage ∧ ¬ avhdr.valid? ∧ avhdr ≠ garbage ∧ emptyleb = buf

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ emptyleb = mkempbuf(LEB_SIZE)

Rule argument

Additional information

Used simplifier rules: ⊦ empty ≠ garbage; (s)% ⊦ ¬ empty.valid?; (s)% ⊦ empty ≠ garbage; (s)% ⊦ ¬ empty.valid?; (s)