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Proof step 111 from proof inv-format (previous step)

# buf1 = EB_PAGE_SIZE, # pebs1 = n + m1, # pebs0 = n + m1, pebs1[m1] = mkpeb(buf0, m2, false), n0 < m1, n0 < n + m1, is-encoded(echdr((err1 = ESUCCESS ∧ aehdr0.valid? ⊃ aehdr0.ec + 1;0)), buf1), mtd-cons(pebs1[m1, mkpeb(copy(buf1, 0, emptypeb, 0, EB_PAGE_SIZE), EB_PAGE_SIZE, false)]), mtd-cons(pebs1[m1, mkpeb(emptypeb, 0, false)]), mtd-cons(pebs1), mtd-cons(pebs0), EB_PAGE_SIZE ≤ PEB_SIZE, ∀ n1. n1 < m1 → ubi-io-peb-initial(pebs1[n1]) ⊦ n = 0, n0 = m1, ubi-io-peb-initial(pebs1[n0])

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 13 terms: n0

Additional information

Used terms: n0