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Proof step 144 from proof inv-format (previous step)

# pebs0 = n0 + m1, # pebs = n0 + m1, pebs[m1] = mkpeb(buf, m, true), mtd-cons(pebs0), mtd-cons(pebs), n ≤ m1, ∀ n. n < # subarray(pebs, 0, m1) → ubi-io-peb-initial(subarray(pebs, 0, m1)[n]) ⊦ n0 = 0, ubi-io-peb-initial(subarray(pebs, 0, m1 + 1)[n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 145:
# pebs = n0 + m1, # pebs0 = n0 + m1, pebs[m1] = mkpeb(buf, m, true), mtd-cons(pebs), mtd-cons(pebs0), n ≤ m1, ∀ n1. n1 < m1 → ubi-io-peb-initial(pebs[n1]) ⊦ n0 = 0, ubi-io-peb-initial(subarray(pebs, 0, m1 + 1)[n])

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)% ⊦ n0 < n → subarray(pebs, m, n)[n0] = pebs[m + n0]; (s)% ⊦ # subarray(pebs, m, n) = n; (s)