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Proof step 148 from proof inv-format (previous step)

# pebs = n0 + m1, # pebs0 = n0 + m1, pebs[m1] = mkpeb(buf, m, true), n < m1 + 1, mtd-cons(pebs), mtd-cons(pebs0), n ≤ m1, n < m1 → ubi-io-peb-initial(pebs[n]) ⊦ n0 = 0, ubi-io-peb-initial(pebs[0 + n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 149:
# pebs = n0 + m1, # pebs0 = n0 + m1, pebs[m1] = mkpeb(buf, m, true), mtd-cons(pebs), mtd-cons(pebs0) ⊦ n0 = 0, ubi-io-peb-initial(mkpeb(buf, m, true))

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m; (s)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ n + 0 = n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ n → (n < m ↔ false); (s)% ⊦ m < n + 1 ↔ ¬ n < m; (s)