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Proof step 64 from proof inv-format (previous step)

# pebs0 = n0 + m1, # pebs1 = n0 + m1, pebs[m0].fill = 0, pebs1[m1] = mkpeb(buf0, m2, false), aehdr = aechdr((err1 = ESUCCESS ∧ aehdr0.valid? ⊃ aehdr0.ec + 1;0)), buf = mkbuf(m), ehdr = echdr(aehdr.ec), m = EB_PAGE_SIZE, m0 = m1, pebs = pebs1[m1, mkpeb(emptypeb, 0, false)], aehdr.valid?, m0 < # pebs, mtd-cons(pebs0), mtd-cons(pebs1), mtd-cons(pebs1[m1, mkpeb(emptypeb, 0, false)]), ubi-io-initial(subarray(pebs1, 0, m1)), m0 < # pebs → aehdr.valid? → m0 < # pebs ∧ (¬ pebs[m0].bad → m0 < # pebs), (err1 = ESUCCESS ∧ aehdr0.valid? ⊃ aehdr0.valid?;true) ⊦ ⟪encode_echeader#(m, ehdr; buf; err); if err = ESUCCESS then mtd_asm_write#(m0, 0, 0, m, buf; pebs; err); m1 := m1 + 1⟫ ( m1 ≤ # pebs0 ∧ # pebs0 = # pebs ∧ mtd-cons(pebs) ∧ (err = ESUCCESS → ubi-io-initial(subarray(pebs, 0, m1))) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ # pebs0 < n0 + m1), n0 = 0, pebs[m0].bad

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 65:
# pebs0 = n0 + m1, # pebs1 = n0 + m1, pebs1[m1] = mkpeb(buf0, m2, false), buf = mkbuf(EB_PAGE_SIZE), n0 ≠ 0, mtd-cons(pebs0), mtd-cons(pebs1), mtd-cons(pebs1[m1, mkpeb(emptypeb, 0, false)]), ubi-io-initial(subarray(pebs1, 0, m1)) ⊦ ⟪encode_echeader#(EB_PAGE_SIZE, echdr(aechdr((err1 = ESUCCESS ∧ aehdr0.valid? ⊃ aehdr0.ec + 1;0)).ec); buf; err); pebs := pebs1[m1, mkpeb(emptypeb, 0, false)]; if err = ESUCCESS then mtd_asm_write#(m1, 0, 0, EB_PAGE_SIZE, buf; pebs; err); m1 := m1 + 1⟫ ( m1 ≤ # pebs0 ∧ # pebs0 = # pebs ∧ mtd-cons(pebs) ∧ (err = ESUCCESS → ubi-io-initial(subarray(pebs, 0, m1))) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ # pebs0 < n0 + m1)

Rule argument

Additional information

Used simplifier rules: ⊦ m < m + n ↔ n ≠ 0; (s)% ⊦ mkpeb(buf, m, boolvar).bad ↔ boolvar; (s)% ⊦ m < # pebs → pebs[m, peb][m] = peb; (s)% ⊦ aechdr(m).valid?; (s)% ⊦ # pebs[n, peb] = # pebs; (s)% ⊦ mkpeb(buf, m, boolvar).fill = m; (s)%m < # pebs ⊦ pebs[m, peb][m] = peb; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + m0 ≤ m ↔ m0 = 0; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)