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Proof step 14 from proof inv-io-read (previous step)

# buf2 = n1 + n0 + n, # buf = # buf2, pebs[m3] = mkpeb(buf1, m2, false), buf0 = buf2, err0 = EIO, m = m4, m1 = m3, m5 = 0, m3 < # pebs, m1 < # pebs, mtd-cons(pebs), range=(buf, 0, buf2, 0, n0), range=(buf, n0 + n, buf2, n0 + n, # buf2 - n0 + n), n0 + n ≤ # buf2, m0 + n ≤ PEB_SIZE, n0 + n ≤ # buf, m ≤ UBI_READ_RETRIES + 1, m ≤ UBI_READ_RETRIES, err = ESUCCESS → subarray(buf, n0, n) = subarray(pebs[m1].data, m0, n), err = ESUCCESS ∨ ⌊err⌋ ⊦ ⟪mtd_asm_read#(m1, m0, n0, n, pebs; buf; bitflips, err); if err ≠ ESUCCESS then debug#("ubi-io: failed to read from PEB " + m1.toString); m := m +1⟫ ( ( m1 < # pebs ∧ ¬ pebs[m1].bad ∧ m0 + n ≤ PEB_SIZE ∧ n0 + n ≤ # buf ∧ m ≤ UBI_READ_RETRIES + 1 ∧ # buf = # buf2 ∧ range=(buf, 0, buf2, 0, n0) ∧ range=(buf, n0 + n, buf2, n0 + n, # buf2 - n0 + n) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → subarray(buf, n0, n) = subarray(pebs[m1].data, m0, n))) ∧ UBI_READ_RETRIES + 1 - m < UBI_READ_RETRIES + 1 - m4), err = ESUCCESS, pebs[m1].bad

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
# buf2 = n1 + n0 + n, # buf = # buf2, pebs[m3] = mkpeb(buf1, m2, false), m3 < # pebs, mtd-cons(pebs), range=(buf, 0, buf2, 0, n0), range=(buf, n0 + n, buf2, n0 + n, # buf2 - n0 + n), m0 + n ≤ PEB_SIZE, n0 + n ≤ # buf2, m4 ≤ UBI_READ_RETRIES + 1, m4 ≤ UBI_READ_RETRIES, ⌊err⌋ ⊦ ⟪mtd_asm_read#(m3, m0, n0, n, pebs; buf; bitflips, err); if err ≠ ESUCCESS then debug#("ubi-io: failed to read from PEB " + m3.toString); m := m4 + 1⟫ ( n0 + n ≤ # buf ∧ m ≤ UBI_READ_RETRIES + 1 ∧ # buf = # buf2 ∧ range=(buf, 0, buf2, 0, n0) ∧ range=(buf, n0 + n, buf2, n0 + n, # buf2 - n0 + n) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → subarray(buf, n0, n) = subarray(pebs[m3].data, m0, n)) ∧ UBI_READ_RETRIES < (UBI_READ_RETRIES - m4) + m)

Rule argument

Additional information

Used simplifier rules: ⊦ mkpeb(buf, m, boolvar).bad ↔ boolvar; (s)% ⊦ m + n < m + n0 ↔ n < n0; (s)%n0 ≤ n ⊦ n - n0 < m ↔ n < m + n0; (s)% ⊦ m ≤ n → (n < m ↔ false); (s)% ⊦ m ≤ n ↔ ¬ n < m; (ss)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n ≤ m → m + n0 - n = (m - n) + n0; (s)% ⊦ m +1 = m + 1; (s)% ⊦ ⌊err⌋ → err ≠ ESUCCESS; (s)