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Proof step 26 from proof inv-io-read (previous step)

# buf2 = n2 + n0 + n, # buf = # buf2, UBI_READ_RETRIES = n1 + m4, pebs[m3] = mkpeb(buf1, m2, false), err = err0, m3 < # pebs, mtd-cons(pebs), range=(buf, 0, buf2, 0, n0), range=(buf, n0 + n, buf2, n0 + n, n2), m1 + n ≤ PEB_SIZE, n0 + n ≤ # buf2, m4 ≤ UBI_READ_RETRIES + 1, m4 ≤ UBI_READ_RETRIES, ⌊err1⌋ , ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err = ESUCCESS then buf := copy(pebs[m3].data, m1, buf, n0, n) else choose buf1 with # buf1 = # buf2 ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, # buf2 - n0 + n) in buf := buf1; if err ≠ ESUCCESS then debug#("ubi-io: failed to read from PEB " + m3.toString); m := m4 + 1⟫ ( n0 + n ≤ # buf ∧ m ≤ UBI_READ_RETRIES + 1 ∧ # buf = # buf2 ∧ range=(buf, 0, buf2, 0, n0) ∧ range=(buf, n0 + n, buf2, n0 + n, n2) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → subarray(buf, n0, n) = subarray(pebs[m3].data, m1, n)) ∧ UBI_READ_RETRIES < n1 + m)

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

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