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Proof step 3 from proof inv-io-read (previous step)

buf0 = buf, m < # pebs, mtd-cons(pebs), n0 + n ≤ # buf, m0 + n ≤ PEB_SIZE, ¬ pebs[m].bad ⊦ ⟪ubi_io_read#(m, m0, n0, n, pebs; buf; bitflips, err)⟫ ( # buf = # buf0 ∧ range=(buf, 0, buf0, 0, n0) ∧ range=(buf, n0 + n, buf0, n0 + n, # buf0 - n0 + n) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → subarray(buf, n0, n) = subarray(pebs[m].data, m0, n)))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
# buf0 = n1 + n0 + n, buf0 = buf, m < # pebs, mtd-cons(pebs), m0 + n ≤ PEB_SIZE, n0 + n ≤ # buf, n0 + n ≤ # buf0 ⊦ ⟪ubi_io_read#(m, m0, n0, n, pebs; buf; bitflips, err)⟫ ( # buf = # buf0 ∧ range=(buf, 0, buf0, 0, n0) ∧ range=(buf, n0 + n, buf0, n0 + n, n1) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → subarray(buf, n0, n) = subarray(pebs[m].data, m0, n))), pebs[m].bad

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [# buf0, n0 + n, n1]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: # buf0, n0 + n, n1