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Proof step 31 from proof inv-io-read (previous step)

# buf = # buf2, # buf2 = n2 + n0 + n, UBI_READ_RETRIES = n1 + m4, pebs[m3] = mkpeb(buf1, m2, false), err = ESUCCESS, err = err0, m3 < # pebs, mtd-cons(pebs), range=(buf, n0 + n, buf2, n0 + n, n2), range=(buf, 0, buf2, 0, n0), m4 ≤ UBI_READ_RETRIES, m4 ≤ UBI_READ_RETRIES + 1, n0 + n ≤ # buf2, m1 + n ≤ PEB_SIZE, n0 + n ≤ # buf, m1 + n ≤ # pebs[m3].data, ⌊err1⌋ , ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ n0 + n ≤ # copy(pebs[m3].data, m1, buf, n0, n) ∧ m4 + 1 ≤ UBI_READ_RETRIES + 1 ∧ # copy(pebs[m3].data, m1, buf, n0, n) = # buf2 ∧ range=(copy(pebs[m3].data, m1, buf, n0, n), 0, buf2, 0, n0) ∧ range=(copy(pebs[m3].data, m1, buf, n0, n), n0 + n, buf2, n0 + n, n2) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → subarray(copy(pebs[m3].data, m1, buf, n0, n), n0, n) = subarray(pebs[m3].data, m1, n)) ∧ UBI_READ_RETRIES < n1 + m4 + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
# buf = # buf2, # buf2 = n2 + n0 + n, UBI_READ_RETRIES = n1 + m4, pebs[m3] = mkpeb(buf1, m2, false), m3 < # pebs, mtd-cons(pebs), range=(buf, n0 + n, buf2, n0 + n, n2), range=(buf, 0, buf2, 0, n0), m4 ≤ UBI_READ_RETRIES, m4 ≤ UBI_READ_RETRIES + 1, n0 + n ≤ # buf2, m1 + n ≤ PEB_SIZE, ⌊err1⌋ ⊦ range=(copy(buf1, m1, buf, n0, n), 0, buf2, 0, n0) ∧ range=(copy(buf1, m1, buf, n0, n), n0 + n, buf2, n0 + n, n2)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ n < n; (s)%n < # pebs ⊦ pebs[n] = mkpeb(buf, m, boolvar) ∧ mtd-cons(pebs) → # buf = PEB_SIZE; (s)% ⊦ m < n → (n ≤ m ↔ false); (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ mkpeb(buf, m, boolvar).data = buf; (s)% ⊦ m < n + 1 ↔ ¬ n < m; (s)%m1 + n ≤ # buf ⊦ subarray(copy(buf0, m0, buf, m1, n), m1, n) = subarray(buf0, m0, n); (s)% ⊦ m ≤ n → (n < m ↔ false); (s)% ⊦ m ≤ n ↔ ¬ n < m; (ss)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n ≤ n0 ∧ n1 ≤ m → n + n1 ≤ n0 + m; (s)% ⊦ # copy(buf, m, buf0, m0, n) = # buf0; (s)% ⊦ ¬ ⌊ESUCCESS⌋ ; (s)