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Proof step 54 from proof inv-io-read (previous step)

# buf = # buf2, # buf2 = n2 + n0 + n, UBI_READ_RETRIES = n1 + m4, pebs[m3] = mkpeb(buf1, m2, false), m3 < # pebs, mtd-cons(pebs), range=(buf, n0 + n, buf2, n0 + n, n2), range=(buf, 0, buf2, 0, n0), m4 ≤ UBI_READ_RETRIES, m4 ≤ UBI_READ_RETRIES + 1, n0 + n ≤ # buf2, m1 + n ≤ PEB_SIZE, ⌊err1⌋ , ⌊err0⌋ ⊦ ∃ buf1. # buf1 = # buf2 ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, # buf2 - n0 + n)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 55:
# buf2 = n2 + n0 + n, # buf = # buf2, # buf2 = n3 + n0 + n, UBI_READ_RETRIES = n1 + m4, pebs[m3] = mkpeb(buf1, m2, false), m3 < # pebs, mtd-cons(pebs), range=(buf, 0, buf2, 0, n0), range=(buf, n0 + n, buf2, n0 + n, n2), m1 + n ≤ PEB_SIZE, n0 + n ≤ # buf2, m4 ≤ UBI_READ_RETRIES + 1, m4 ≤ UBI_READ_RETRIES, ⌊err0⌋ , ⌊err1⌋ ⊦ ∃ buf1. # buf1 = # buf2 ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, n3)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [# buf2, n0 + n, n3]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: # buf2, n0 + n, n3