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Proof step 16 from proof initial-ex-abstract-initial (previous step)

m0 + 1 = # pebs, ubi-io-initial(pebs) ⊦ ∀ n. n < # subarray(pebs, 0, m0) → ubi-io-peb-initial(subarray(pebs, 0, m0)[n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
m0 + 1 = # pebs, n < m0, ubi-io-initial(pebs) ⊦ ubi-io-peb-initial(pebs[n])

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)% ⊦ n0 < n → subarray(pebs, m, n)[n0] = pebs[m + n0]; (s)% ⊦ # subarray(pebs, m, n) = n; (s)