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Proof step 3 from proof initial-ex-abstract-initial (previous step)

0 = # pebs, ubi-io-initial(pebs) ⊦ ∃ apebs. abs(pebs, apebs) ∧ ubi-io-initial(apebs)

User applied rule exists right

And obtained the following new goals

Proof step 4:
0 = # pebs, ubi-io-initial(pebs) ⊦ abs(pebs, mkapebs(0)) ∧ ubi-io-initial(mkapebs(0))

Rule argument

pos: right 1 terms: mkapebs(0) abort: F discard: T computed: F

Additional information

Used terms: mkapebs(0)