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Proof step 59 from proof initial-ex-abstract-initial (previous step)

m0 + 1 = # pebs, pebs[m0] = mkpeb(buf, m, true), n < m0, abs(subarray(pebs, 0, m0), apebs), ubi-io-initial(pebs), n < # apebs → ubi-io-peb-initial(apebs[n]) ⊦ n = m0, ubi-io-peb-initial(apebs[n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 60:
m0 + 1 = # pebs, pebs[m0] = mkpeb(buf, m, true), n < m0, # apebs < m0, abs(subarray(pebs, 0, m0), apebs), ubi-io-initial(pebs), # apebs ≤ n ⊦ n = m0, ubi-io-peb-initial(apebs[n])

Rule argument

Additional information

Used simplifier rules: fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat% ⊦ m < n ↔ ¬ n ≤ m; (ss)