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Proof step 6 from proof initial-ex-abstract-initial (previous step)

0 = # pebs, ubi-io-initial(pebs) ⊦ (# pebs = # mkapebs(0) ∧ (∀ n. n < # pebs → abs-peb(pebs[n], mkapebs(0)[n]))) ∧ ubi-io-initial(mkapebs(0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
0 = # pebs, ubi-io-initial(pebs) ⊦ ubi-io-initial(mkapebs(0))

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m < 0; (s)% ⊦ # mkapebs(n) = n; (s)