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Proof step 62 from proof initial-ex-abstract-initial (previous step)

m0 + 1 = # pebs, abs(subarray(pebs, 0, m0), apebs), ubi-io-initial(pebs), ubi-io-initial(apebs) ⊦ pebs[m0].bad, ∃ apebs. abs(pebs, apebs) ∧ ubi-io-initial(apebs)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: peb name: elim seq: ⊦ (buf = peb.data ∧ m = peb.fill) ∧ (boolvar ↔ peb.bad) ↔ peb = mkpeb(buf, m, boolvar) subst: [peb, buf, m, boolvar] → [pebs[m0], buf, m, boolvar]

Additional information

Used simplifier rules: ⊦ (buf = peb.data ∧ m = peb.fill) ∧ (boolvar ↔ peb.bad) ↔ peb = mkpeb(buf, m, boolvar); (elim) Used terms: pebs[m0], buf, m, boolvar