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Proof step 66 from proof initial-ex-abstract-initial (previous step)

m0 + 1 = # pebs, ubi-io-initial(pebs) ↔ (∀ n. n < # pebs → ubi-io-peb-initial(pebs[n])), pebs[m0] = mkpeb(buf, m, false), abs(subarray(pebs, 0, m0), apebs), ubi-io-initial(apebs), ubi-io-initial(pebs) ⊦ ∃ apebs. abs(pebs, apebs) ∧ ubi-io-initial(apebs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 67:
m0 + 1 = # pebs, pebs[m0] = mkpeb(buf, m, false), abs(subarray(pebs, 0, m0), apebs), ubi-io-initial(apebs), ubi-io-initial(pebs), ∀ n. ¬ m0 < n → ubi-io-peb-initial(pebs[n]) ⊦ ∃ apebs. abs(pebs, apebs) ∧ ubi-io-initial(apebs)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m < n + 1 ↔ ¬ n < m; (s)