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Proof step 68 from proof initial-ex-abstract-initial (previous step)

m0 + 1 = # pebs, pebs[m0] = mkpeb(buf, m, false), abs(subarray(pebs, 0, m0), apebs), ubi-io-initial(pebs), ubi-io-initial(apebs), ¬ m0 < m0 → ubi-io-peb-initial(pebs[m0]) ⊦ ∃ apebs. abs(pebs, apebs) ∧ ubi-io-initial(apebs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 69:
m0 + 1 = # pebs, pebs[m0] = mkpeb(buf, m, false), abs(subarray(pebs, 0, m0), apebs), ubi-io-initial(apebs), ubi-io-initial(pebs), ubi-io-peb-initial(mkpeb(buf, m, false)) ⊦ ∃ apebs. abs(pebs, apebs) ∧ ubi-io-initial(apebs)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ n < n; (s)